How many quarts of pure antifreeze must be added to 6 quarts of a 10% antifreeze solution to obtain a 60% antifreeze solution?

X +0,1 (6)=0,3 (x +6) Simplify and solve for x. X +0,6=0,3 x +1,8 Subtract 0,3 x from both sides.0,7 x +0,6=1,8 Subtract 0,6 from both sides.0,7 x=1,2 Finally, divide both sides by 0,7 x=1,71429So you'll need to add 1,71429 quarts of pure antifreeze to the 6 quarts of 10% antifreeze solution to obtain 7,71429 (6+1,71429) quarts of 30% antifreze solution.