Sin (3 x +2)=cos (4 x-10) so we have to findvalue of x, in order todo so we have to somehow cancel sin andcos terms on b/s so icansin (3 x +2)=sin (pi/2+(4 x-10) as sin (pi/2+ x)=cosx->3 x +2=pi/2+4 x-103 x +2-4 x +10=pi/2->x=12-pi/2 alsosin (3 x +2)=sin (pi/2- (4 x-10) 3 x +2+4 x-10=pi/27 x-8=pi/2 x={ (pi/2)+(8) }/7